原本没有想过要用@Query来查询的，毕竟JpaRepository提供的方法已经基本够用了。但是今天这个sql比较特殊可能要用正则匹配，然后看到了ExampleMatcher里的StringMatcher：
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| public static enum StringMatcher {
/**
* Store specific default.
*/
DEFAULT,
/**
* Matches the exact string
*/
EXACT,
/**
* Matches string starting with pattern
*/
STARTING,
/**
* Matches string ending with pattern
*/
ENDING,
/**
* Matches string containing pattern
*/
CONTAINING,
/**
* Treats strings as regular expression patterns
*/
REGEX;
}
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有正则REGEX，我以为这样就很好办了（讲道理sql用正则真的非常慢）。然而事情并不是这么简单。因为会报一个异常Unsupported StringMatcher REGEX。
上面的枚举时有REGEX，但是QueryByExamplePredicateBuilder类的这部分代码:
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| switch (exampleAccessor.getStringMatcherForPath(currentPath)) {
case DEFAULT:
case EXACT:
predicates.add(cb.equal(expression, attributeValue));
break;
case CONTAINING:
predicates.add(cb.like(expression, "%" + attributeValue + "%"));
break;
case STARTING:
predicates.add(cb.like(expression, attributeValue + "%"));
break;
case ENDING:
predicates.add(cb.like(expression, "%" + attributeValue));
break;
default:
throw new IllegalArgumentException(
"Unsupported StringMatcher " + exampleAccessor.getStringMatcherForPath(currentPath));
}
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可以看到并没有REGEX，这是什么骚操作？
所以，我打算使用@Query。在官网文档找到如下示例：
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| public interface UserRepository extends JpaRepository<User, Long> {
@Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1",
countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
nativeQuery = true)
Page<User> findByLastname(String lastname, Pageable pageable);
}
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按照示例写好，然后一运行。非常好，报错了Cannot use native queries with dynamic sorting and/or pagination in method...
看下报错地方的代码：
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| public NativeJpaQuery(JpaQueryMethod method, EntityManager em, String queryString,
EvaluationContextProvider evaluationContextProvider, SpelExpressionParser parser) {
super(method, em, queryString, evaluationContextProvider, parser);
Parameters<?, ?> parameters = method.getParameters();
boolean hasPagingOrSortingParameter = parameters.hasPageableParameter() || parameters.hasSortParameter();
boolean containsPageableOrSortInQueryExpression = queryString.contains("#pageable")
|| queryString.contains("#sort");
if (hasPagingOrSortingParameter && !containsPageableOrSortInQueryExpression) {
throw new InvalidJpaQueryMethodException(
"Cannot use native queries with dynamic sorting and/or pagination in method " + method);
}
}
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从这段代码里看出，报异常的原因时我们的sql里没有#pageable
所以，加上这个就好了，修改后的代码如下：
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| public interface UserRepository extends JpaRepository<User, Long> {
@Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 \n#pageable\n",
countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
nativeQuery = true)
Page<User> findByLastname(String lastname, Pageable pageable);
}
|
